We let  be a  sphere in Euclidean three space. We want to obtain
a picture of the sphere on a flat piece of paper or a plane.
Whenever one projects a higher dimensional object onto a lower dimensional object, some type of distortion must occur. There are a number of different ways to project and each projection  preserves some things and distorts others.
 Later  we will explain why we choose stereographic
 projection, but first we describe it.
 be a  sphere in Euclidean three space. We want to obtain
a picture of the sphere on a flat piece of paper or a plane.
Whenever one projects a higher dimensional object onto a lower dimensional object, some type of distortion must occur. There are a number of different ways to project and each projection  preserves some things and distorts others.
 Later  we will explain why we choose stereographic
 projection, but first we describe it.
We shall map the  sphere  onto the plane containing its equator. 
 Connect a typical point
 onto the plane containing its equator. 
 Connect a typical point  on the surface of the sphere to the north pole
 on the surface of the sphere to the north pole  by a straight line in three space. This line will intersect the equatorial plane at some point
 by a straight line in three space. This line will intersect the equatorial plane at some point  . We call
. We call  the projection of
 the projection of  .
.
 Using this recipe
every point of the sphere except the North pole projects to some point on the equatorial plane. Since we  want to include the North pole in our picture,  we add an extra point  ,  called 
 the point at infinity,  to the equatorial  plane 
 and we view
,  called 
 the point at infinity,  to the equatorial  plane 
 and we view  as the image of
 as the image of  under stereographic projection.
 under stereographic projection.
 to be the unit sphere,
 to be the unit sphere,  so that
  so that   plane is  the equatorial plane.  The typical point
 plane is  the equatorial plane.  The typical point  on the sphere
has coordinates
 on the sphere
has coordinates  . The typical point
. The typical point  in the equatorial plane, whose coordinates are
 in the equatorial plane, whose coordinates are  , will be called
, will be called  .
.
  .
. 
 .
.
 .
.
 For this to be true where do we have to think of  as lying:  interior to
 as lying:  interior to  or exterior to it?
 or exterior to it?
 -axis?
-axis?
 What projects onto the  ?       
Call the set of points that project onto
?       
Call the set of points that project onto  the prime meridian.
 the prime meridian.
 -axis?
onto any vertical line, not necessarily the
-axis?
onto any vertical line, not necessarily the  axis?
 axis?
Stereographic projection preserves circles and angles. That is, the image of a circle on the sphere is a circle in the plane and the angle between two lines on the sphere is the same as the angle between their images in the plane. A projection that preserves angles is called a conformal projection.
We will outline two proofs of the fact that stereographic projection preserves circles, one algebraic and one geometric. They appear below.
Before you do either proof, you may want to clarify in your own mind what a circle on the surface of a sphere is. A circle lying on the sphere is the intersection of a plane in three space with the sphere. This can be described algebraically. For example, the sphere of radius 1 with center at the origin is given by
An arbitrary plane in three-space is given by
 for some arbitrary choice of the constants  ,
, ,
, 
 , and
, and  . 
Thus a circle on the unit sphere is any set of points whose coordinates 
simultaneously satisfy equations  2 and  3.
. 
Thus a circle on the unit sphere is any set of points whose coordinates 
simultaneously satisfy equations  2 and  3.
The fact that the  points  ,
,  and
 and  all lie on one line can be expressed by the fact that
 all lie on one line can be expressed by the fact that
for some non-zero real number  . (Here
. (Here  .)
.)
The idea of the proof is that one can 
use   equations  2 and  4 to write  as a function of
 as a function of  and
 and  ,
,  as a function of
 as a function of  and
 and  , and
, and  as a function of
 as a function of  and
to simplify equation  3 to an equation in
 and
to simplify equation  3 to an equation in  and
 and  .
 Since the equation in
.
 Since the equation in  and
 and  so obtained is clearly the equation of a circle in the
 so obtained is clearly the equation of a circle in the  plane, the projection of the intersection of  2 and  3 is a circle.
 plane, the projection of the intersection of  2 and  3 is a circle.
To be more precise:
 Equation  4 says that  .
Set
.
Set   and verify that
 and verify that

If

lies on the plane,

Thus

Or

Whence,

Or

Recalling that

, we see
Since the coefficients of the

and the

terms are the same, this is the equation of a circle in the plane.
The geometric proofs sketched below use the following principle:
It doesn't really make much difference if instead of projecting onto the equatorial plane, we project onto another horizontal plane (not through N), for example the plane that touches the sphere at the South pole, S. Just what difference does this make?
 , we
project onto the horizontal plane
, we
project onto the horizontal plane  through
 through  .  Then by symmetry
the tangent planes
.  Then by symmetry
the tangent planes  and
 and  at
 at  and
 and  make the same angle
 make the same angle  with
with  , as also does
, as also does  , by properties of parallelism (see figure # 1 at the end of this handout).
, by properties of parallelism (see figure # 1 at the end of this handout).
  So  and
 and  are images of each other in the (``mirror'') plane
 are images of each other in the (``mirror'') plane  through
through  and perpendicular to
 and perpendicular to  .
.
  For a point  on the sphere near
 on the sphere near  , the line
, the line  is nearly parallel to
 is nearly parallel to  , so that for points near
, so that for points near  , stereographic projection is approximately 
the reflection in
, stereographic projection is approximately 
the reflection in  .
.
 is where some cone touches the sphere, say the cone
of tangent lines to the sphere from a point
 is where some cone touches the sphere, say the cone
of tangent lines to the sphere from a point  .
.
Now project onto the horizontal plane  through
 through  .
.
In figure # 2  which NEED NOT be a vertical plane,
the four angles  are equal, for the same reasons as before, so that
 are equal, for the same reasons as before, so that
 . The image of
. The image of  is therefore the horizontal circle of the
same radius centered at
 is therefore the horizontal circle of the
same radius centered at  .
.
 in the
circle of radius
 in the
circle of radius  centered at
 centered at  is the unique point
 is the unique point  on the
ray
 on the
ray  for which
 for which   .
.