3D Flux through a Plane
Recall that if we have fluid flowing in some 3D region, then the
velocity of the fluid defines a vector field. We can compute
the flux of the fluid across some surface by integrating
the normal component of the velocity along the
surface. The flux tells us the total amount of fluid to cross the
boundary in one unit of time.
Although an electric field does not contain fluid, it is useful to
use the concept of flux to describe the "amount" of electric field
that passes through a surface. Loosely speaking, the electric flux
determines the intensity of the electric field on a surface.
Again, picture a positive unit of charge at the origin and a negative
unit of charge at (x,y,z)=(2,0,0). The full 3D electric potential
generated by these charges is proportional to
In Maple
we can define the electric potential and field
by
V:= 1/(4*Pi*sqrt(x^2+y^2+z^2)) - 1/(4*Pi*sqrt((x-2)^2+y^2+z^2));
EField:= grad( -V, [x,y,z] );
In the following exercise, you will determine the electric flux
through the (infinite) plane defined by x=1.
We will follow the same steps we followed in class.
Question #2
For your lab report, write down the answers to each of the steps below
in order to compute the flux through the plane x=1. (You may
include a Maple
worksheet, but please describe in words
what each computation means.)
- Define g to be a (vector-valued) expression
in s,t that
parametrizes the plane defined by x=1. Hint:
if
g
is the Maple
expression that
defines the parametrization, then plotting
plot3d( g, s=-1..1, t=-1..1 );
should give you a portion of the plane x=1.)
- To find the electric field at an arbitrary point on the
plane, substitute your parametrization into your expression for
the electric field. For example
F:= subs(x=g[1],y=g[2],z=g[3], eval(EField));
will probably work.
- Let n be the unit normal to the plane. Since there are two
normals that you could choose, let's all choose the one that
points towards large values of x.
- Define A to be the expression that gives the area of
the parallelogram formed by tangent vectors to the parametrized
plane. Hint: Although in general this expression will be a
complicated function of
the two parameters, A will probably be very simple
for your parametrization of the plane.
- The total flux across the surface is a double integral.
In terms of what we've done so far, the quantity to integrate
is
integrand:= innerprod(F,n)*A;
- If we integrate this quantity over the plane, we get the total
flux. To aid in visualizing what is happening:
- Integrate the
integrand
over the square
defined by x=1, -L < y < L,
and -L < z < L. You may be able to simplify
the resulting expression more than Maple
can!
- Plot this expression for 0 < L <
100. Describe what the plot tells us about the flux
through the plane
- near the x-axis
- far away from the x-axis
- Take the limit as L increases to infinity in
order to determine the flux through the infinite plane.
Hint: The total flux should be a very simple expression!
Next: Flux through a Box
Up: Introduction
Previous: Electromagnetic Potentials
Robert E. Thurman<thurman@geom.umn.edu>
Document Created: Fri Mar 31 1995
Last modified: Mon Apr 14 10:54:16 1997