3D Flux through a Plane

Recall that if we have fluid flowing in some 3D region, then the velocity of the fluid defines a vector field. We can compute the flux of the fluid across some surface by integrating the normal component of the velocity along the surface. The flux tells us the total amount of fluid to cross the boundary in one unit of time.

Although an electric field does not contain fluid, it is useful to use the concept of flux to describe the "amount" of electric field that passes through a surface. Loosely speaking, the electric flux determines the intensity of the electric field on a surface.

Again, picture a positive unit of charge at the origin and a negative unit of charge at (x,y,z)=(2,0,0). The full 3D electric potential generated by these charges is proportional to

In Maple we can define the electric potential and field by

  V:= 1/(4*Pi*sqrt(x^2+y^2+z^2)) - 1/(4*Pi*sqrt((x-2)^2+y^2+z^2));
  EField:= grad( -V, [x,y,z] );

In the following exercise, you will determine the electric flux through the (infinite) plane defined by x=1. We will follow the same steps we followed in class.


Question #2

For your lab report, write down the answers to each of the steps below in order to compute the flux through the plane x=1. (You may include a Maple worksheet, but please describe in words what each computation means.)
  1. Define g to be a (vector-valued) expression in s,t that parametrizes the plane defined by x=1. Hint: if g is the Maple expression that defines the parametrization, then plotting
    plot3d( g, s=-1..1, t=-1..1 );
    should give you a portion of the plane x=1.)
  2. To find the electric field at an arbitrary point on the plane, substitute your parametrization into your expression for the electric field. For example
    F:= subs(x=g[1],y=g[2],z=g[3], eval(EField));
    will probably work.
  3. Let n be the unit normal to the plane. Since there are two normals that you could choose, let's all choose the one that points towards large values of x.
  4. Define A to be the expression that gives the area of the parallelogram formed by tangent vectors to the parametrized plane. Hint: Although in general this expression will be a complicated function of the two parameters, A will probably be very simple for your parametrization of the plane.
  5. The total flux across the surface is a double integral. In terms of what we've done so far, the quantity to integrate is
    integrand:= innerprod(F,n)*A;
  6. If we integrate this quantity over the plane, we get the total flux. To aid in visualizing what is happening:

Next: Flux through a Box
Up: Introduction
Previous: Electromagnetic Potentials

Robert E. Thurman<thurman@geom.umn.edu>
Document Created: Fri Mar 31 1995
Last modified: Mon Apr 14 10:54:16 1997