(n + 1)Expanding and simplifying gives us^{2}+ (n + 2)^{2}= n^{2}+ (n - 1)^{2}+ (n - 2)^{2}

n(n-12) = 0The only acceptable solution is n = 12. The five consecutive whole numbers are

10, 11, 12, 13 and 14

Source: Berrondom, Marie

Categories: Number sense, Square numbers, Algebra

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