3 0i }&5c apm3 {%U[$HjDI4D̜P ;Copyright 1996 - Michael D. Huberty, Ko Hayashi & Chia VangngiH iÌiYPipG LEstimation of PiPi`R6ile ics Apps Math Apps etwork Apps User Temp AppD*oAlength of one side of inscribed polygon = diameter x sin(180/n) length of one side of circumscribed polygon = diameter x tan(180/n) where n is the number of sides of the polygon.n.rverTs`ts`@t )s6H;MC `0CC =B"change radius"D#CH=B AZx>NnNr pF NrNs PFDC <B j [NnNuP0XNDCD#C?C7h4e"oJ MD H ;oL0toJ`oCCB?5%F?5%Fc9OpO| DbHOpOqO|OODCB?5%F?5%F ? m7]B0pO]8 E4/h]B]BPO]8ebra and Pas] Circumference C = @ N $(B@circumference of circle = @$$($ #`p(((@/| 2L e2LD(D ((56 sc!3   | P& P!! "(e @[2L6  5 "t!x $ D($ P556+'D P6;' c@ ; MDt lh@oK@ }$oI oC݀C` _duZ "change angle"D\CfD J-c2N @F DbNN0 FNC݀C`B!?5%F?5%F 5GO' av ITX; ZhOX9X; OCCC݀C`? ^B ap IO IhOOOD#CD\Cf? U-d m32U P@[ E4U 0U  [UU #m{!:A}change radiusAchange angle = @ N $(B@angle = rence of circle = @$$($ #`p(((@/| 2L e2LD(D ((56 sc!3   | P& P!! "(e @[2L6  5 "t!x $ D($ P556+'D P Bd ao IDOg IOeOgODCD\Cf? Nb@ ; MDdt lh@oK@ }$oI oCZFCVB  Nd@ ; MDt lh@oK@ }$oI oC%C\ Yc10O΀O@ DbpPO`OO@`ObC݀C`B ?5%F?5%F VeRe m40cscsNI{|  {D:360}{Angle} = sAchange angle = @ N $(B@n = e = rence of circle = @$$($ #`p(((@/| 2L e2LD(D ((56 sc!3   | P& P!! "(e @[2L6  5 "t!x $ D($ P556+'D P@eHc3N F DbN`N FNCZFCVBB?5%F?5%FO AIOHHOOP0OCQ4C_ Na@ ; MDt lh@oK@ }$oI oCNCVQ G;! au IX9 KlpX5X9 OCCCQ4C_?G;' asX3 pO]8 DbHX3X3 PO]8XXCCCˊC? ; ar HOـ KOؐOـepPC݀C`CQ4C_? G; aq KO` Higsaw PuzzleOO`@OCCCQ4C_?eHc4N F DbNNp FNCNCVQB?5%F?5%F X4 AJX4HHOX5 0XCCK 6;N@f@ ; MDt lh@oK@ }$oI oCYC 8ile  a7s Apps Math Apps etwork Apps User TempAppl CCB?f1C݀C`CQ4C_AuAm? y' at O]8X1@@@@@@h`PCιXC`C/Cܱ?hKc5N `F DbNN @F NCYCB?5%F?5%Fr- m30XO]8 E4XX0O]8X fc = 0}{Angle} = sAchange angle = @ N $(B@ diameter = ce of circle = @$$($ #`p(((@/| 2L e2LD(D ((56 sc!3   | P& P!! "(e @[2L6  5 "t!x $ D($ P556+'D P 5; anXO]8 DbXXPO]8XCYCC݀C`? X>PALX>0HHOX>0XC3 CV !6;X=@AKX= HHOX=p0XCC! !5; baCC!C݀C`? & az J[^ h0[[[^[CQ4C_C3 CV?%$  m44{T CalculatorSWSW`{`TLSW  {D:Circumference C}{fc} = angle = @ N $(B@#(Circumference of unit circle)/2 = @$$($ #`p(((@/| 2L e2LD(D ((56 sc!3   | P& P!! "(e @[2L6  5 "t!x $ D($ P556+'D P #Ne@ ; MDt lh@oK@ }$oI oCC "_n<  m35ff33  fc{!:*}tan{(:{D:Angle}{2}} = gle = @ N $(B@length of circumscribed side = 2 = @$$($ #`p(((@/| 2L e2LD(D ((56 sc!3   | P& P!! "(e @[2L6  5 "t!x $ D($ P556+'D P1#^m  m34}#OO`@OLKLLO^K^^^J22kOO  fc{!:*}sin{(:{D:Angle}{2}} = gle = @ N $(B@length of inscribed side = e = 2 = @$$($ #`p(((@/| 2L e2LD(D ((56 sc!3   | P& P!! "(e @[2L6  5 "t!x $ D($ P556+'D P8#5G; ay[arctan[-abs[sqrt[ln[log[round[nCC!CC?&; ax KXDЫ \XBXD OCC!C3 CV?%&' aw HX? IX;`X? OC3 CVCC!?&%ARe m42cscsNI{|  'n{!:*}(length of circumscribed side) = @ N $(B@%perimeter of circumscribed polygon = @$$($ #`p(((@/| 2L e2LD(D ((56 sc!3   | P& P!! "(e @[2L6  5 "t!x $ D($ P556+'D P+~>Re m41cscsNI{|  #n{!:*}(length of inscribed side) = ) = @ N $(B@!perimeter of inscribed polygon = n = @$$($ #`p(((@/| 2L e2LD(D ((56 sc!3   | P& P!! "(e @[2L6  5 "t!x $ D($ P556+'D P,&Re m45cscsNI{|  ,{D:(perimeter of circumscribed side)}{fc} = @ N $(B@;(perimeter of polygon circumscribed about unit circle)/2 = $$($ #`p(((@/| 2L e2LD(D ((56 sc!3   | P& P!! "(e @[2L6  5 "t!x $ D($ P556+'D P0##  m4333̙ff33  ({D:(perimeter of inscribed side)}{fc} = } = @ N $(B@4(perimeter of polygon inscribed in unit circle)/2 = e)/2 = $$($ #`p(((@/| 2L e2LD(D ((56 sc!3   | P& P!! "(e @[2L6  5 "t!x $ D($ P556+'D P1#