N -k&'capmwHZwwDoo%;TP p(@oJl D[T0TPO]X 08<T><80 T O @bA midsegment of a triangle is parallel to the third side and is half the length of the third side.O]XT"ile !(@oJl ics Apps Math Apps etwork Apps User Temp AppDo Triangle Midsegment Conjecture: re: A midsegment of a triangle is parallel to the third side and is half the length of the third sid!b!(@oJl AbpHHOXb0bA ?D!!(@oJl Bbbh8OXbpbbM<%bAB ?D!(@oJl C CaptionsScribbO@O /bbCB !(@oJl Db gbPbp`b _bpb@b-C afO!(@oJl BCcBO!(@oJl AC+CRSXO!(@oJl CCCR Am>!(@oJl bRelabelebbbb))!..3&Point H is the midpoint of segment BC.0J,b bbb`KHOdOOFKb!(@oJl H is tb bpbP@@<@bp@"@bb &Point J is the midpoint of segment AB.B.bb`bPb PbPiLbb@0bPb b /b+.!(@oJ l bϰStyles/bɀbbϰJbɀ  0346Segment q is called the midsegment of a triangle. . 4|AAAAB@BAbɠPbCCDAb`DyD{DDECEyV`tP!(@oJ l ~ iLPoCancelPPu@ PEpOPoPvP PP+,rA midsegment has the following properties: 1. The length of the midsegment is half the length of the third side.Pu Pv PPv Pu F4 dPvPw0 P 08<Pw0><80 O!(@oJ l PdpPeI PbPd@ ZLabel:PPP22. The midsegment is parallel to the third side. Ox/Pd@PdPePcPeiLPa Use Subscriptile !(@oJl BCrCPq!(@oJl AC2DPsP!(@oJl CCDB=<! (@oJl DbbѠb bh8Obb@bP ,%bDIf the measure of the segments p and s are equal and the segments p and s are constructed perpendicular to segment q, then segment q is parallel to segment n.gment AC.Ztb@bPbPb` K@bAJDDJ!(@oJl  T.POO`OT+T,NPT{T,T%T, N0T0IDrag the point C, in the above figure, to change the length of the sides and angles of the triangle. What do you notice about the relationship between segment q and segment n? ,PT1OOTT,OPT. k T1OO OT,T, T2T.P{/Jigs!l(@oJl @T9p Note PadT.T3  T9pT30T9pnt DocumentsTTcTDrag point C, in the above figure, to change the lengths of segments q and n. What happens to the relationship of their lengths?PgxKHH4T4 eLOO.E!(@oJl T8 BT{OOT+` 1.18 inchesT8 `T0Is there more than one midsegment of a triangle?T2T8T?T8 T8T?OT8 T9a!f&ile !(@oJl Ycs Apps Math Apps etwork Apps User Temp AppDCDX!(@oJl ZO b0b bbC&DmRW!(@oJl TCDm 7c ! (@oJl :Pcc 0hc cIDrag any point on the triangle above to see if segment l is a midsegment.t.ccc  gc ic@ h%<O!(@oJl c h Hcc i4 5cc-Are there any more midsegments of a triangle?  )*dec@`c)*decc`@c*,bdc ,bW\!(@oJl YCD ~U!(@oJl ZCDRWU!(@oJl TCD 0!(@oJl T[pUO4O0OTOȨUUUUUT[@UFDrag on any point on the triangle to see if segment x is a midsegment.t.ZU@T TTZU@T  TTT ZUD! !(@oJl jbpb KE bPbbbbOAAB?>Db !(@oJl k;biLTablesbbOtO/bABCB?DO !(@oJl lO;O O;p b@POTbpbbCBC?  !(@oJl m@b@b@ bb bpb@0Z`CA?XPB !(@oJl nDbHPB@PC@PFPB@PC00PFPCCRC+CR?5(| `OƠ !(@oJl IC+CRCcB?zoM`Xile !(@oJl pcs Apps Math Apps etwork Apps User Temp AppDCcBCCR? ile !(@oJl wcs Apps Math Apps etwork Apps User Temp AppDCrCC2D? !(@oJl nC2DCD?IAPICT !(@oJl you should be able to open it wit any drawing program.PPPCDCrC?`& !(@oJl aec c Db0c c pcccCDXC&Dm?W !(@oJl afc `cOOOc cC&DmCDm?` W !(@oJl zCDmCDX?Y?j V}ile !(@oJl kCD CD? p.}WO !(@oJl ajGc#c(c" HHO8CDCD?VWO$ !(@oJl akc40c.HHOŴcCDCD ? !(@oJ l H@bPb0b0b@bbCC %!(@oJ l I User Temp AppleCD Audo PlayerAutomated Tasks CalCGC $;@ps!(@oJl HCC (nt D!(@oJl ICRC&m*| (@oJl m12PP S E4!P0PˠS蠫 P n = p@4BloB0t oJoDT3oCoIoDToCOzoC` Length(Segment n) = oC (voC 7h zXD $oC 0)d)`90 loE }( `O'4VxoE"H p oD0 H }\$BoC oD0oJ90(h loE 0 } |BoD0 0oJ90(oh 0'mQ| (@oJl m14PԐ0PՀP@PԐ  n = p@4BloB0t oJoDT3oCoIoDToCOzoC` Length(Segment n) = oC (voC 7h zXD $oC 0)d)`90 loE }( `O'4VxoE"H p oD0 H }\$BoC oD0oJ90(h loE 0 } |BoD0 0oJ90(oh 0# !(@oJl AB60T{CCT?CaZ`waZ`wAW?CdDc  ) !(@oJl AC2T{(²TB0 ?dGTC}Dm *uTN (@oJl m15TLHHO|TN0T z = p@4BloB0t oJoDT3oCoIoDToCOzoC` Length(Segment z) = oC (voC 7h zXD $oC 0)d)`90 loE }( `O'4VxoE"H p oD0 H }\$BoC oD0oJ90(h loE 0 } |BoD0 0oJ90(oh 0+!(@oJl AI User Temp AppleCD Audo PlayerAutomated Tasks CalCjD -(-!(@oJl AJ User Temp AppleCD Audo PlayerAutomated Tasks CalCDP . 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