.V  capm 0>~iKu!s 8@tlulator ChooserContol Pane Ӆ0 .7Move points A,B & C to adjust the size of the triangle.ӂӅPӇCaps NӅ0Ӆ0ӇӅ0nt DocumӆpLm# 8@t{  JrConjectures: The perpendicular bisectors of a triangle intersect at the same point (G) called the circumcenter. The circumcenter is the same distance from the triangle's vertices thus making it the center of the circle that circumscribes the triangle. ڜ@@Pmړڞ@  J0A xch  8@tCknown}{false}ifelse/sk exch def/{bind def}bind def/sa{matrix currentmat C3C6 qavf  8@tB """ "D "" " oD-e """ "3tABB 49oint 8@tACenter+RadiusTMInteriorBXC`BB? 8@tFc?a?C C KP 8@tE00>yc03321fF03381f0331f0331f133fBC)  sx 8@tD3f`31f`30`32cf`1f`BCK  ' S{ 8@tpntersection Point t MidpointnSegment/Ray/LiC CBC ? f' 8@tnACCC@? M'! 8@tmC,BBC<ݙ lq31 8@tG3f>f2131fff3330fff032fff{>1>>fFBۿ0C7G, ) 8@tm10_ ` E4$$__p`_ CG =  @@K@, P;8( @\Pl6@;.33"3""@lj-V1#:#@Distance(C to G) = N@3(0@KNdPp-V(10@u 0pP@KD\p@< T"-V -V!@DT>8@V\ ?@-?s(@h 8@$H0h@,@ dh`Dt d@** d@!@z d@,  8@tm9VP` E4$$VW@0`V  BG =  @@K@, P;8( @\Pl6@;.33"3""@lj-V1#:#@Distance(B to G) = N@3(0@KNdPp-V(10@u 0pP@KD\p@< T"-V -V!@DT>8@V\ ?@-?s(@h 8@$H0h@,@ dh`Dt d@** d@!@z d@,  8@tm8N` E4$$NpN`Np AG =  @@K@, P;8( @\Pl6@;.33"3""@lj-V1#:#@Distance(A to G) = N@3(0@KNdPp-V(10@u 0pP@KD\p@< T"-V -V!@DT>8@V\ ?@-?s(@h 8@$H0h@,@ dh`Dt d@** d@!@z d@, k  8@tradius(2D Bۿ0C7G,C3C6? xUUUU 8@tm6UUUUUUUUUUUUUUUUT@UUUUUUUUUUUUUUUUTA  m{!:A}CDG = @@K@, P;8( @\Pl6@;.33"3""@lj-V1#:#@ Angle(CDG) = G) = N@3(0@KNdPp-V(10@u 0pP@KD\p@< T"-V -V!@DT>8@V\ ?@-?s(@h 8@$H0h@,@ dh`Dt d@** d@!@z d@,  D0 8@t0@ r) 8@t c1 On Object {Point t Intersection Point At MoBۿ0C7G,BF?5%F?5%F