) " capm &xjt&x6&!n SH@*Are there times when you notice a relationship between the squares of the two legs of the triangle and the square of the hypotenuse? Drag the vertices of your triangle so that the relationship exists. Now look at the measures of angles A, B, and C. Is there anything special about the angles? Find a different triangle that satisfies the relationship with the squares of the legs and the hypotenuse. Take a look at the angle measures of this triangle. How do they compare to the measures of the angles of the previous triangle? Are you ready to make a conjecture about the squares of the legs and hypotenuse of the triangle and the measure of its angles? If so, test out your conjecture on some more triangles. If you're not ready, take a look at some more triangles and see if you can find a pattern.`@`P@'@)@`(!@n(%RhWhile you are changing the lengths of the sides of the triangle, keep your eye on the following things: The measures of the angles The value of a^2 + b^2 The value of c^2 0p(' 1ȃ`T)~!n( < QUse the pointer tool to grab a vertex and change the length of a side. For this exercise, you will want to keep side c as the longest side of the triangle.~kpnBD C j`nCCmCrwsnA Network Apps User TemAppleCD Audio PlayerAutomdCC0!nm12^0R E4sz]^P0Rgv! m{!:A}CBA = dD$@$@ 0 0` Y` mTHH43 Ű Do0t `@|?D DB 4dY g4( 7D h )ǀ$ g$ 0 g\:!nm10ZSSWS`HHh| m{!:A}CAB = dD$@$@ 0 0` Y` mTHH43 Ű Do0t `@|?D DB 4dY g4( 7D h )ǀ$ g$ 0 g\1!nm9N0@R E4tNN@R`t+ m{!:A}ACB = dD$@$@ 0 0` Y` mTHH43 Ű Do0t `@|?D DB 4dY g4( 7D h )ǀ$ g$ 0 g\qN ncD CCC?[ n naCmCD C?ܺ.w  nbCCCmC?I$I$D Vg!nm4`0 P` c = A}ACB = dD$@$@ 0 0` Y` Length(Segment c) = hDD D$@$@dň 4Pw_d ep ``D14:>THH43 Ű Do0t `@|?D DB 4dY g4( 7D h )ǀ$ g$ 0 g\  &h!nm3 E4pAbout Sketca = A}ACB = dD$@$@ 0 0` Y` Length(Segment a) = hDD D$@$@dň 4Pw_d ep ``D14:>THH43 Ű Do0t `@|?D DB 4dY g4( 7D h )ǀ$ g$ 0 g\ . @`!nm10 E4b = A}ACB = dD$@$@ 0 0` Y` Length(Segment b) = hDD D$@$@dň 4Pw_d ep ``D14:>THH43 Ű Do0t `@|?D DB 4dY g4( 7D h )ǀ$ g$ 0 g\ 2H>!nm7  Calculatorgh Lg  c{u:2} = = dD$@$@ 0 0` Y` Length(Segment c)^2 = hDD D$@$@dň 4Pw_d ep ``D14:>THH43 Ű Do0t `@|?D DB 4dY g4( 7D h )ǀ$ g$ 0 g\ !nm6 @ Calculatorgg Lg  b{u:2} = = dD$@$@ 0 0` Y` Length(Segment b)^2 = hDD D$@$@dň 4Pw_d ep ``D14:>THH43 Ű Do0t `@|?D DB 4dY g4( 7D h )ǀ$ g$ 0 g\!nm5  Calculator@ L  a{u:2} = = dD$@$@ 0 0` Y` Length(Segment a)^2 = hDD D$@$@dň 4Pw_d ep ``D14:>THH43 Ű Do0t `@|?D DB 4dY g4( 7D h )ǀ$ g$ 0 g\-=!nm8\0S CalculatorIJ\S LI a{u:2} + b{u:2} = dD$@$@ 0 0` Y` 0(Length(Segment a)^2) + (Length(Segment b)^2) = DD D$@$@dň 4Pw_d ep ``D14:>THH43 Ű Do0t `@|?D DB 4dY g4( 7D h )ǀ$ g$ 0 g\