d1 = (multiple of 9) + 4 d2 = (multiple of 9) + 6Number of photographs:
d1 x d2 = (multiple of 9) + (4 x 6)
= (multiple of 9) + (18 + 6)
= (multiple of 9) + 6
The photographer therefore exposed six frames on his last film.
There are three frames left.