U -k !)capm h } !AI$$HHbC6D@ =B$P!PCD@ $"!C$!HHb$"00$C3C ty!QCC 7{<$-p!ABC !I) P0$ $ KNNOCC r!Js@sAtt@{{@|||@|A}}}A}BADC ?:!  DD[04Parallelogram Conjecture IV:: p۷ # @`P b 4=1#S   T T TC Tf T T=LThe daigonals of a parallelogram are bisected by their point of intersectionT VJ@`Vv @ V Ve oppo% %`(8<mp  |`xPHHqTz`TUe The point O is the point of intersection of the diagonals of this parallelogram It is claimed that the point O bisects AC and BD. Is this true? Drag the points P and Q to change the shape of the parallelogram. Compare the lengths of the two blue segments AO and CO. Compare the lengths of the two red segments BO and OD. What happens?C Tf T Tݿ@ %:0%`%438q`!WPHHpBT  1368Refl!X Center AF Mark Mirror G- Mark Vector Mark Distance MBTBL 1B6Gp!YPHHpDBL BGP!Zp/ D  /ile !ics Apps Math Apps etwork Apps User Temp AppDoSides AB and CD Dtor poserControl Panels Find FileJigsaw Puzzle No0 !ics Apps Math Apps etwork Apps User Temp AppDoSides AD and BC Dtor poserControl Panels Find FileJigsaw Puzzle$\low !r close unne#@#put awa desk##`#p#p#e !( Opposite Sides: Red: Blue: ounts of##0#p 9@#p`vH`# 0Ld4a`v%3 |ut a!AAs, and do whatever else seems apropriate to free up memory. Saving opsCŀC  !ABp# 0#@##CŀD I Np!ACp0[pDD |IN!AD Yr Xs DC '!j$ p J$ p J$$C6D@CD@?!''!k<$"$!@9$C3CCC?B  !lJ$"TN0T ?C6D@CD@?s8 !m>6#$, pC3CCC? !zAB@A@@@ACCDC?268 !aap0|BT BTBL? 026G !abPPPBTBLDBL? A6G !acpx0`DBLD ? 2G !adpHHp 0D BT ? {  !aeq`0CŀCCŀD? N !afqP0PCŀDDD?{H N !agq0pDDDC?{N !ah; ,P;bpJ-?D DCCŀC?6<' !n !$*qBbCCAC?E'' !ob $.`CGBCGCEp'BBC@C1C?!c1$90 Db$9p$9=t=$$BCC_q?5%F?5%F!c2$=  Dbg $=$=p?v-! AEHHs8CŀCπ IN?BU! AF24 Q"7@ ,bpbpDCπ !$>@! BCeCR$%7< $D0! DCC #&Nn !aiC P"6` ,b|btpbD}CŀCπDCπ?)(<  !ajafpm%YuGeometry CentergeomCeCRCC?֪+*' !pSelect Chil$:D- Hide ToolboxShow ClipboardC CRCCR?*ۊ'' !q#p #$?0+;Graph Create Axes- ShorCRC@CC?+z<  !rtion Buttons$PPturePcturesunusedunusedsunusedunusedsundCeCRBC?*6z<  !sM| m0PS E4PPBCCC?+Xz<' !v$0O Db$$Op$BCCN#Cϊ?*+!c4$@ Db$ $`D$CeCRA(?5%F?5%F* R!c6$`` Db$@$@?yz$CCA(?5%F?5%F+lq$J !CCCR ./%*! K `$bb$b<\ WCCj 0'-2$! L$HHa|$0$C#vC 2'7<$! M$ HH`$0$CC 1'$! S$ҠHH`$0$CS9Cc, 037<$! V$ڠHH_$0$ClC 14z<q ! ak@CCRBC?5<q !td# 0M8#CCCCR?5+q< !u6#CCRCeCR?*5' !w$K Dbow$$@KtructAlread$iCeCRCrDCs`?5*}q !x$p8P Db{$P$80AB$ACCRCn|Cs`?+5*p<  !y$, Db$$`,$  $.CCCxDCϊ?5+U!c5$ Db$$ bNs0$CCRA(?5%F?5%F5'9! a1$@ Db$ $Ɛ`C_CW$+BCA(?lȾaCCCCjAAp/ dS?876  ! OCuC;-SX$Ƞ! N$ȀHH_$0$C}qCR =AUZ$ɰ! O$ɐHH`$0$CnEC[ ?AZ_$! P$ʠHH`$0$CCc, <Aa! QNU^  W@!PWC~CR =3$Ѱ! R$ѐHH_$0$CnCi#v >3%*$ؠ! T$؀HH_$0$CwCj <4 %$ٰ! U$ِHH`$0$C|{+CE @4z< ! aoBCCuC?C q ! anCCRCuC?C5<  ! am`0CuCCC?+C  ! al ,m%lm%Ҁ%CeCRCuC?C*U\! a2$@ DbJ$ $ΐ` n P h$CCQA)l>mC}qCRCCc,AA U?FED! a3$@ Db$ $֐`$0 $CeCRA(>x?lCS9Cc,C~CRA A?9HG 9! a4$@ Db$ $ސ`$ހ $ CCA(mlCwCjClCAp2A@ S ?:JII m12%@ـ E4% %`% H m {S:AO} = h >N  >$ B@ \dLength(Segment AO) = > ,Ȥ?$ $ %>p( (@X>b>d>B ;P%>DD 6$>Ȥ>>r$>>0t #_?3 > >Ȥ &>PȤ>P??>" ;P @e z> ?\ 9p ?\>$w> 7 zD $>P ސKH m11%Pp E4%0%P% H m {S:CO} = h >N  >$ B@ \dLength(Segment CO) = > ,Ȥ?$ $ %>p( (@X>b>d>B ;P%>DD 6$>Ȥ>>r$>>0t #_?3 > >Ȥ &>PȤ>P??>" ;P @e z> ?\ 9p ?\>$w> 7 zD $>P ސLI m10%`` E4%@%@% H m {S:OD} = h >N  >$ B@ \dLength(Segment OD) = > ,Ȥ?$ $ %>p( (@X>b>d>B ;P%>DD 6$>Ȥ>>r$>>0t #_?3 > >Ȥ &>PȤ>P??>" ;P @e z> ?\ 9p ?\>$w> 7 zD $>P ސMI m9%pP E4 %P%0%P %R H m {S:BO} = h >N  >$ B@ \dLength(Segment BO) = > ,Ȥ?$ $ %>p( (@X>b>d>B ;P%>DD 6$>Ȥ>>r$>>0t #_?3 > >Ȥ &>PȤ>P??>" ;P @e z> ?\ 9p ?\>$w> 7 zD $>P ސN